Question

What is the length of a diagonal brace that could be used for a wall 9 feet high and 12 feet long?

Answer choices:
1) 15 ft
2) 13 ft
3) 12 ft
4) 14 ft

Answer 1

The correct answer is option 1.

Explanation:

Height of the wall = p = 9 ft (Perpendicular)

length of the of the base of the wall = b = 12 ft (Base)

Length of the diagonal brace = h = ?(Hypotenuse)

Applying Pythagoras theorem ;

`(Hypotenuse)^2=(Perpendicular)^2+(Base)^2`

`(Hypotenuse)^2=(9 ft)^2+(12 ft)^281 ft^2+144 ft^2`

`(Hypotenuse)=√(225 ft^2)=15 ft`

15 feet is the length of a diagonal brace.