Question

When an antacid tablet dissolves in water, the fizz is due to a reaction between sodium hydrogen carbonate (sodium bicarbonate, NaHCO3) and citric acid (H3C6H5O7). 3 NaHCO3(aq) H3C6H5O7(aq) 3 CO2(g) 3 H2O(l) Na3C6H5O7(aq) How many moles of Na3C6H5O7 can be produced if one tablet containing 0.0370 mol of NaHCO3 is dissolved

Answer 1

When a tablet containing 0.0370 mol of NaHCO3 dissolves in water, it produces 0.0370 mol Na3C6H5O7.

Step-by-step explanation:

When a tablet containing 0.0370 mol of NaHCO3 dissolves in water, it reacts with the citric acid (H3C6H5O7) to produce sodium citrate (Na3C6H5O7) along with carbon dioxide (CO2) and water (H2O). The balanced chemical equation for this reaction is:

3 NaHCO3(aq) + H3C6H5O7(aq) → 3 CO2(g) + 3 H2O(l) + Na3C6H5O7(aq)

From the balanced equation, we can see that for every 3 moles of NaHCO3, 1 mole of Na3C6H5O7 is produced. Therefore, if one tablet containing 0.0370 mol of NaHCO3 is dissolved, it will produce:

0.0370 mol Na3C6H5O7

Answer 2

Answer : The moles of
`Na_3C_6H_5O_7` produced can be, 0.0123 mole

Explanation : Given,

Moles of
`NaHCO_3` = 0.0370 mol

The given balanced chemical reaction is:

`3NaHCO_3(aq)+H_3C_6H_5O_7(aq)\rightarrow 3CO_2(g)+3H_2O(l)+Na_3C_6H_5O_7(aq)`

From the balanced chemical reaction we conclude that,

As, 3 moles of
`NaHCO_3` react to give 1 mole of
`Na_3C_6H_5O_7`

So, 0.0370 moles of
`NaHCO_3` react to give
`(0.0370)/(3)* 1=0.0123mole` of
`Na_3C_6H_5O_7`

Thus, the moles of
`Na_3C_6H_5O_7` produced can be, 0.0123 mole