Circle the GCF of 28x3 and 16x2y2 28x3: 2.2.7.••* 16x2y2:2.2.2.2.x.x.y.y

Question

asked Aug 22, 2021 116k views

2 Answers

Johnarleyburns · Answer 1 · 2021-08-26T16:57:54+0000

Answer:

Explanation:

28x^3 = 2 * 2 * 7 * x * x * x

16x^2Y^2 = 2 * 2 * 2 * 2 * x * x * y *y

GCF = 2 * 2 * x *x = 4x^2

Circle which are in both