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39 votes
39 votes
Find rhe area of a cjircle of radius 35 cm if a sector of angle80 is removed from the circle what area is left



User Secant Zhang
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2.9k points

2 Answers

18 votes
18 votes

Removed area


\\ \sf\longmapsto A=(\theta)/(360)\pi r^2


\\ \sf\longmapsto A=(80)/(360)\pi r^2


\\ \sf\longmapsto A=(2)/(9)\pi r^2

Left area.


\\ \sf\longmapsto \pi r^2-(2)/(9)\pi r^2


\\ \sf\longmapsto \pi r^2(1-2/9)


\\ \sf\longmapsto \pi r^2(7/9)


\\ \sf\longmapsto 7/9(35)^2\pi


\\ \sf\longmapsto 952.7\pi cm^2

User Chuck Burgess
by
2.9k points
20 votes
20 votes

Answer:

  • 2991.72 cm²

Explanation:

Find the area left:

  • A =
  • πr² - 80/360*πr² =
  • πr²(1 - 2/9) =
  • 7/9πr² =
  • 7/9*3.14*35² =
  • 2991.72 cm²
User Benjymous
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2.6k points