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Jesse estimates the weight of her cat to be 10 pounds. The actual weight of the cat is 13.75.Find the percent of error.

User Morhook
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1 Answer

3 votes

Answer:

The percent error is 27.27%

Explanation:

I did this by using the formula actual-estimated value/actual value

In this case it would be 3.75/13.75 and I got .2727 and then had to multiply by 100 (to find percent not decimal form) and got 27.27%

User Fsaravia
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