Question

Two hikers are 14 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walks 2.8 mph faster than the other.

Answer 1

df

Step-by-step explanation:

Answer 2

The rate of one is 2.1 mph and the rate of the other is 4.9 mph

Step-by-step explanation:

Let the rate of one be y mph

The rate of the other = (y+2.8) mph

Total rate = y + y + 2.8 = (2y+2.8) mph

Total rate = distance apart/time

2y + 2.8 = 14/2

2y + 2.8 = 7

2y = 7 - 2.8

2y = 4.2

y = 4.2/2 = 2.1 mph

The rate of the other is y+2.8 = 2.1+2.8 = 4.9 mph