Answer:
![(arctan^2(x))/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3bv59r6xwpwzqpl2gp6v883d8wtcutcm3i.png)
Explanation:
For this question, set u = arctan(x). This would be the easiest way because the derivative of arctan(x) is
which is what we have. Before setting u, always look at the question and think about possible derivatives.
![\int(arctanx)/(x^2+1)dx \ Let \ u = arctan(x)\\\\\\u = arctan(x) \ \ \ du = (1)/(x^2+1)dx\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ifaf55bnqqkor2clguz9qxjb9yk48kxyev.png)
Next, plug in u and du.
(rearranging)
![\int u\ du](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3yowokq645cv3ciqu07k5d2gl5he74jsrg.png)
![= (u^2)/(2) = (1)/(2)u^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/741bejs5k7yipmx246yhc96y8gs7j965be.png)
Substitute arctan(x) back in for u and add +C.
![(arctan^2(x))/(2)+C](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b481cgpvtojdy3ppa0h66zkyz8knd9x7qi.png)