Question

#1. bring the fraction: b / 7a^2c to a denominator of 35a^3c^3

#2. bring the fraction: a / a−4 to a denominator of 16−a^2

Answer 1

Part A: Term
`5ac` is used to bring denominator of
`35a^(3) c^(3)`

Part B: Term
`a+4` is used to bring denominator of
`16-a^(2)`

Step-by-step explanation:

Part A: To bring the fraction
`(b)/(7a^(2)c )` to a denominator of
`35a^(3) c^(3)`, we need to multiply the denominator by the term
`5ac`

The term
`5ac` is determined by
`(35a^(3) c^(3))/(7a^(2)c )}` which equals
`5ac`

Thus, the fraction becomes

`(b)/(7a^(2)c )*(5ac)/(5ac) =(5abc)/(35a^(3) c^(3))`

Thus, the term
`5ac` is used to bring denominator of
`35a^(3) c^(3)`

Part B: To bring the fraction
`(a)/(a-4)` to a denominator of
`16-a^(2)`, we need to multiply the denominator by
`a+4`

Thus, we have,

`(a)/(a-4)*(a+4)/(a+4) =(a(a+4))/(16-a^(2))`

Thus, the term
`a+4` is used to bring denominator of
`16-a^(2)`