Question

A pump contains 0.5 L of air at 203 kPa . You draw back on the piston of the pump, expanding the volume until the pressure reads 50.8 kPa . What is the new volume of air in the pump?

Answer 1

V₂ = 2 L

Step-by-step explanation:

given,

P₁ = 203 kPa

V₁ = 0.5 L

Now, volume is expanded

P₂ = 50.8 kPa

V₂ = ?

Using Boyle's law

P₁V₁ = P₂ V₂

`V_2 = (P_1V_1)/(P_2)`

inserting all the values

`V_2 = (203* 0.5)/(50.8)`

V₂ = 2 L

Hence, new volume of air in the pump is equal to 2 L.