Answer:
Step-by-step explanation:
we have that angular velocity that ω = 2πf
where f = 1/t, and t = 3.15 × 10⁷ sec/year
But the Earths revolution speed around the sun is given about 29.78 km/s
this velocity V₁ = 2πr/T
where T = 1 year
And the Earth rotates at a speed of 360° in 1 day(24 hrs)
from the angular velocity ω = 2πf
ω = 7.292 × 10⁻5 rad/sec ............(1)
The maximum distance from axis of rotation of the earth at the equator is given req = 6378 m
Measuring the Shifts as a result of the Earth surface movement at equator;
V₂ = ωr
V₂ = 7.292 × 10⁻5 ˣ 6378 = 0.465 km/s
V₂ = 0.465 km/s
From this we have that the maximum effect of the Earth's motion around the sun and it's rotation will be
Vt = V₁ + V₂
Vt = 29.72 + 0.465 = 30.2 km/s
Vt = 30.2 km/s
(b). As the latitude increases, the velocity shift decreases.
Step-by-step explanation:
Moving away from the equator towards the pole direction, we figure that the distance of the surface decreases with rotation speed. That is to say that at the poles we have a zero value and at the equator we get a maximum value.