Question

How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?

Answer 1

0.665 moles of CO₂

Step-by-step explanation:

The balance chemical equation for the combustion of Ethane is as follow:

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: Calculate moles of C₂H₆ as;

Moles = Mass / M.Mass

Putting values,

Moles = 10.0 g / 30.07 g/mol

Moles = 0.3325 moles

Step 2: Calculate Moles of CO₂ as;

According to balance chemical equation,

2 moles of C₂H₆ produced = 4 moles of CO₂

So,

0.3325 moles of C₂H₆ will produce = X moles of CO₂

Solving for X,

X = 0.3325 mol × 4 mol ÷ 2 mol

X = 0.665 moles of CO₂