Answer:
Explanation:
given that U, V are two vectors in R^n
These two vectors can be written as a linear combination of 3 vectors
w1, w2, and w3
To prove that U+V also can be written as a linear combination of these three vectors.
Since U is a linear combination we can write for not all a,b, c equal to 0
![U = aw1+bw2+cw3](https://img.qammunity.org/2021/formulas/mathematics/college/qg6c78z09fo2bpqq8o45xdq0qxnuzev3dz.png)
Similarly for d,e,f not all equal to 0
![V= cw1+dw2+ew3](https://img.qammunity.org/2021/formulas/mathematics/college/cb1dt61dfsxn7axntfsykoz94s7y01iolr.png)
Adding these we have
![U+V =(a+d)w1 + (b+e) w2+(c+f)w3](https://img.qammunity.org/2021/formulas/mathematics/college/tzxh8s34dnwrf27fnuk6tn55ad0u9ak9d1.png)
Here all a+d, b+e or c+f cannot be simultaneously 0.
So we get U+V can be written as a linear combination of w1, w2 w3 as follows:
![U+W = gw1+hw2+iw3 \\g = a+d\\h = b+e\\i = c+f](https://img.qammunity.org/2021/formulas/mathematics/college/7416sjpe3hhwhob0mgvsc749skfpktxbz5.png)
Proved