Question

n the metric system the acceleration due to gravity near Earth's surface is about 9.81 meters per second per second. What is the acceleration due to gravity as measured in the English system, that is, in feet per second per second? (Round your answer to one decimal place.)

Answer 1

`32.2(ft)/(s^2)`

Step-by-step explanation:

To do this conversion we have to know that:

`1ft=0.3048m`

(It is easy to find this value on physics textbooks or internet physics webpages)

So, we should convert the gravitational acceleration in the next way:

`9.81(m)/(s^(2))=9.81(m)/(s^(2))*(1ft)/(0.3048m)`

So, the meters cancel out:

`9.81(m)/(s^(2))=9.81(1)/(s^(2))*(1ft)/(0.3048)=32.18(ft)/(s^2)`

`9.81(m)/(s^(2))=32.2(ft)/(s)`