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What is the mole fraction of I2 in a solution made by dissolving 55.6 g of I2 in 245 g of hexane, C6H14?

User SuperCow
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1 Answer

1 vote

Answer:

The answer to your question is X = 0.072

Step-by-step explanation:

Data

X I₂ = ?

mass of I₂ = 55.6 g

mass of hexane = 245 g

Formula

X I₂ = (moles of Iodine) / (moles of iodine + moles of hexane)

Process

1.- Convert the mass of reactants to moles

atomic mass of I₂ = 2 x 127 = 254g

atomic mass of hexane = (12 x 6) + (14 x 1) = 86 g

254 g ---------------- 1 mol

55.6 g------------- x

x = (55.6 x 1)/254

x = 0.22 moles of I₂

86 g ------------- 1 mol

245 g ------------- x

x = (245 x 1)/86

x = 2.84 moles

2.- Calculate the mole fraction of I₂

X = 0.22 / (0.22 + 2.84)

X = 0.22 / 3.07

X = 0.072

User Jdeng
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