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Write an equation of a line that is through (6,-3) and is perpendicular to 3x+y=6

User Fabla
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1 Answer

6 votes

Answer: y=-1/3x-1

Explanation:

1) Isolate y by subtracting 3x from both sides.

3x+y=6 -> y=3x+6

2) Find the negative inverse of 3- which is -1/3.

3) Use y=mx+b and plug in what you know.

-3=-1/3(6)+b

4) Solve for b.

-3=-2+b

-1=b

5) Put it all together in y=mx+b format.

y=-1/3x-1

User Edoloughlin
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