Question

An airplane, starting from rest, moves down the runway at constant acceleration for 18 s and then takes off at a speed of 60 m/s. What is the average acceleration of the plane?

Answer 1

Step-by-step explanation:

Given

Airplane runs for a time period of
`t=18\ s`

Airplane takes off with a velocity of
`v=60\ m/s`

It is given that airplane starts from rest i.e. initial velocity
`u=0`

acceleration is the rate of change of velocity thus it is given by

`a=(v-u)/(t)`

`a=(60-0)/(18)`

`a=3.33\ m/s^2`

Average acceleration for 18 s is
`3.33 m/s^2`

Answer 2

a =3.33 m/s²

Step-by-step explanation:

given,

initial speed of Plane, u = 0 m/s

final speed of plane, v = 60 m/s

time of the acceleration, t = 18 s

average acceleration of the plane, a = ?

average acceleration is equal to change in velocity per unit time.

`a = (v - u)/(t)`

`a = (60 - 0)/(18)`

`a = (60)/(18)`

a =3.33 m/s²

Hence, average acceleration of the plane is equal to a =3.33 m/s²