Answer:
The kinetic energy dissipated is 3286.5 J
Step-by-step explanation:
K.E before collision = 1/2m1v1^2 = 1/2×313×6^2 = 5634 J
K.E after collision = 1/2(m1+m2)v2^2
From the law of conservation of momentum:
m1+m2 = m1v1/v2 = 313×6/2.5 = 751.2 kg
K.E after collision = 1/2×751.2×2.5^2 = 2347.5 J
K.E dissipated = 5634 J - 2347.5 J = 3286.5 J