Question

Carbon monoxide (CO) is a poisonous gas because it binds very strongly to the oxygen carrier hemoglobin in blood. A concentration of 8.00 × 102 ppm by volume of carbon monoxide is considered lethal to humans. Calculate the volume in liters occupied by carbon monoxide in a room that measures 10.99 m long, 18.97 m wide, and 11.89 m high at this concentration

Answer 1

Answer: The amount of CO that is occupied in the room is
`1.98* 10^3L`

Step-by-step explanation:

We are given:

Concentration of CO =
`8.00* 10^2ppm=800pm` by volume

This means that
`800\mu L\text{ or }800* 10^(-6)` of CO is present in 1 L of blood

To calculate the volume of cuboid, we use the equation:

`V=lbh`

where,

V = volume of cuboid

l = length of cuboid = 10.99 m

b = breadth of cuboid = 18.97 m

h = height of cuboid = 11.89 m

`V=10.99* 18.97* 11.89=2478.83m^3`

Converting this into liters, by using conversion factor:

`1m^3=1000L`

So,
`2478.83m^3=2.479* 10^6L`

Applying unitary method:

In 1 L of blood, the amount of CO present is
`800* 10^(-6)`

So, in
`2.479* 10^6L` of blood, the amount of CO present will be =
`(800* 10^(-6))/(1)* 2.479* 10^(6)=1983.2L=1.98* 10^3L`

Hence, the amount of CO that is occupied in the room is
`1.98* 10^3L`