Question

A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final volume of the solution is 576 mL.

Answer 1

The mole fraction of fructose in the solution is approximately 0.0165, calculated by dividing the moles of fructose (0.509 moles) by the total number of moles of both fructose and water (0.509 + 30.25 moles).

Step-by-step explanation:

To determine the mole fraction of fructose, we first need to calculate the number of moles of both fructose and water.

The molar mass of fructose (C₆H₁₂O₆) is roughly 180.16 g/mol. Using this information:

• Number of moles of fructose = mass of fructose / molar mass of fructose

• Number of moles of fructose = 91.7 g / 180.16 g/mol = 0.509 moles of fructose

For water (H₂O), we have a molar mass of about 18.015 g/mol:

• Number of moles of water = mass of water / molar mass of water
• Number of moles of water = 545 g / 18.015 g/mol = 30.25 moles of water

The mole fraction of fructose is calculated by the formula:

Mole fraction of fructose = moles of fructose / (moles of fructose + moles of water)

Mole fraction of fructose = 0.509 / (0.509 + 30.25) = 0.0165

The mole fraction of fructose in this solution is approximately 0.0165.

Answer 2

Mole fraction = 0,0166

Step-by-step explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = 0,509 moles of fructose

545g water × (1mol / 18,02g) = 30,24 moles of water

Thus, mole fraction of fructose is:

`(0,509 moles)/(0,509mol + 30,24mol) = 0,0166`

Mole fraction = 0,0166

I hope it helps!