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Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m n Superscript negative 2 Baseline EndFraction? Assume m not-equals 0, n not-equals 0.

StartFraction m Superscript 5 Baseline Over 162 n EndFraction
StartFraction 1 Over 2 m cubed n EndFraction
StartFraction 8 m Superscript 9 Baseline Over n Superscript 9 Baseline EndFraction
StartFraction 4 m Superscript 8 Baseline Over 3 n cubed EndFraction

2 Answers

7 votes

Answer:

A.) m5/162n

Step-by-step explanation:

User Brocco
by
4.9k points
4 votes

Option a:
(m^(5) )/(162n) is the equivalent expression.

Step-by-step explanation:

The expression is
((3m^(-2) n)^(-3))/(6mn^(-2) ) where
m\\eq 0, n\\eq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,


(3^(-3)m^(6) n^(-3))/(6mn^(-2) )

Cancelling the like terms, we have,


(3^(-3)m^(5) n^(-1))/(6 )

This equation can also be written as,


(m^(5))/(3^(3)6 n^(1) )

Multiplying the terms in denominator, we have,


(m^(5) )/(162n)

Thus, the expression which is equivalent to
((3m^(-2) n)^(-3))/(6mn^(-2) ) is
(m^(5) )/(162n)

Hence, Option a is the correct answer.

User Rwking
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4.7k points