Question

43. Calculate the root mean square velocity (r.m.s.) of 1 mole of CO2 at 270C (mm = 44gmol-1

)

A. 4.12 x 102m/s

B. 12 x 102m/s

C. 5.2 x 102m/s

D. 1.2 x 102m/s​

Answer 1

5.2 x 102m/s

Step-by-step explanation:

v(rms) = square root of 3RT divided molar mass in kg

R =8.3J/molK T = 543 kelvin

3(8.3)(543)/.044=307289 m^2/s^2

square root 5.2X10^2 m/2