Question

PLEASE HELPPP!!!!!! Write an equation of the line passing through point P that is perpendicular to the given line.

P(−1,−2), y=−4x+13

Answer 1

Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13

because of (d)⊥(d1) --> a.(-4)=-1 --> a=
`(1)/(4)`

(d): y=
`(1)/(4)x`+b. (d) pass through P(-1;-2) so we have

-2=(1/4).(-1)+b ---> b=
`(-7)/(4)`

(d) y=
`(1)/(4)x+ (-7)/(4)`