Question

A burglar attempts to drag a 105 kg metal safe across a polished wood ????oor Assume that the coe????cient of static friction is 0.4, the coe????cient of kinetic friction is 0.3, and that the burglar can apply a pushing force of 520 N on the metal safe. What is the acceleration of the metal safe across ????oor?

Answer 1

a = 2.012 m/s²

Step-by-step explanation:

given,

Mass of the metal safe, M = 105 Kg

Pushing Force,F= 520 N

coefficient of kinetic friction, μ_k = 0.3

acceleration of the safe on the floor = ?

frictional force acting on the safe

`f = \mu_kN`

`f = \mu_k* m g`

`f = 0.3* 105 * 9.8`

`f = 308.7 N`

now, Net Force acting on the safe

`F_(net) = F - f`

`F_(net) =520-308.7`

`F_(net) = 211.3\ N`

we know,

F = m a

`a = (F)/(m)`

`a = (211.3)/(105)`

a = 2.012 m/s²

Hence, the acceleration of the safe is equal to a = 2.012 m/s²