Question

A lead pellet is propelled upward vertically by an air rifle with an initial velocity of 14.8 m/s. Find the maximum height for the pellet.

Answer 1

h = 11.16[m]

Step-by-step explanation:

In order to solve this problem we must use the following kinematics equation:

`v_(f) ^(2)= v_(o) ^(2)-2*g*h\\where:\\v_(f) = final velocity = 0\\ v_(o) = initial velocity = 14.8 [m/s]\\g = gravity = 9.81[m/s^2]\\h = elevation [m]\\\\0 = 14.8^(2)-2*9.81*h\\ h=(219.04)/(2*9.81) \\h=11.16[m]`

The key to solving this problem with the above equation is to recognize that the final velocity is zero, at the moment when it reaches maximum height.

Note: the sign of gravitational acceleration is negative because it is acting in the opposite direction to the pellet movement.