Answer:
C₁₅H₂₄O
Step-by-step explanation:
Mass of BHT = 2.001 g
mass of carbon dioxide = 5.995
number of mole of CO₂ = 5.995 / 44.01 = 0.1362 mol
mass of water =1.963 g
number of mole of water = 1.963 / 18.02 = 0.109 mol
mass of carbon = 0.1362 mol × 12.0107 = 1.636 g
mass of hydrogen = 0.109 × 2 × 1.00784 = 0.22 g
mass of oxygen present = 2.001 - 1.636 - 0.22 = 0.145 g
number of mole of oxygen = 0.145 / 16 = 0.009
carbon : hydrogen : oxygen = 0.1362 : 0.218 : 0.009 = 15 : 24 : 1
the emperical formula = C₁₅H₂₄O