Answer:
a)
![0.316](https://img.qammunity.org/2021/formulas/biology/college/iu0dpe8njwdwfjegttkt2pe9cowhwfr9xj.png)
b)
![0.105](https://img.qammunity.org/2021/formulas/biology/college/io46zjf9a8rdwyc6yhz1yt3tnwh8w0kd01.png)
c)
![0.035](https://img.qammunity.org/2021/formulas/biology/college/dazuwo7f50vdxfnmedw3xtqm5889jipblv.png)
d)
![0.0117](https://img.qammunity.org/2021/formulas/biology/college/3sgn8pfn6rclsyw3ycyn397v62x6ggktbb.png)
e)
![0.0039](https://img.qammunity.org/2021/formulas/biology/college/33kkwf0fhpy216wpmqhs8xqusnjauws3ci.png)
Step-by-step explanation:
When two heterozygous plants with genotype Bb are crossed, following offspring are produced
Bb * Bb
BB, Bb, Bb, bb
so the probability of blue offspring is
and the probability of white offspring is
![(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/r8zl28n0vf0ogg71i3r53apxva24c1inf4.png)
a) Probability of all 4 peas as blue
![(3)/(4) * (3)/(4) * (3)/(4) * (3)/(4) \\= (81)/(256) \\= 0.316](https://img.qammunity.org/2021/formulas/biology/college/t4k5rbk6own028snlrgoakxzdexp59bvsu.png)
b) Probability of 3 blue and 1 white
![(3)/(4) * (3)/(4)* (3)/(4)* (1)/(4)\\= (27)/(256) \\= 0.105](https://img.qammunity.org/2021/formulas/biology/college/lfma6pqfsxt79ojb6uoj0cou6pk571iwx6.png)
c) Probability of 2 blue and 2 white
![(3)/(4) * (3)/(4)* (1)/(4)*(1)/(4)\\= 0.035](https://img.qammunity.org/2021/formulas/biology/college/suc0i2q6y0vpgk4ygm4wu8vglktbw570pd.png)
d) Probability of 1 blue and 3 white
![(3)/(4) * (1)/(4) * (1)/(4)* (1)/(4)\\= (3)/(256) \\= 0.0117](https://img.qammunity.org/2021/formulas/biology/college/8dmtx6plti9afazfve1zkwkn33a6yio3l0.png)
e) Probability of all white
![(1)/(4) * (1)/(4) * (1)/(4) * (1)/(4) \\= (1)/(256) \\= 0.0039](https://img.qammunity.org/2021/formulas/biology/college/ywunfgcr3nug18orxagc2g0dfvfsgpd6lt.png)