Question

A piece of a newly synthesized material of mass 25.0 g at 80.0◦C is placed in a calorimeter containing 100.0 g of water at 20.0◦C. If the final temperature of the system is 24.0◦C, what is the specific heat capacity of this new material? 1. 1.20 J/g ◦C 2. 7.46 J/g ◦C 3. 4.76 J/g ◦C 4. 0.30 J/g ◦C 5. 0.84 J/g ◦C

Answer 1

1.Cp₁ = 1.2 J/g.⁰C

Step-by-step explanation:

For new material:

m₁ = 25 g

T₁ = 80⁰C

specific heat of water = Cp₁

For water :

m₂ = 100 g

T₂ = 20⁰C

The final temperature T=24⁰C

We know that specific heat of water Cp₂ = 4.187 kJ/kg.K

The heat lost new material = Heat gain by Water

m₁ Cp₁ ( T₁ - T ) = m₂ Cp₂ (T- T₂)

25 x Cp₁ (80- 24 ) = 100 x 4.817 (24 - 20 )

Cp₁ x 56 = 4 x 4.187 x 4

`C_(p1)=(4* 4.187* 4)/(56)\ kJ/kg.K`

Cp₁ = 1.19 kJ/kg.K

Cp₁ = 1.2 J/g.⁰C