Answer:
Charge on the sphere will be equal to
Step-by-step explanation:
We have given radius of the sphere a = 13 cm
And electric filed 21 cm from the center is
![3.7* 10^3N/C](https://img.qammunity.org/2021/formulas/physics/college/6ldbbexmbyp5foqaen37pmnmr27dn0i93w.png)
So distance from the center r = 21 cm
We have to find the charge on the sphere
As
![r> a](https://img.qammunity.org/2021/formulas/physics/college/qpyffxy9mi3ops2xnmso4tu7ze2nrrol8d.png)
So according to Gauss law electric field is equal to
![E=(1)/(4\pi \epsilon _0)(q)/(r^2)](https://img.qammunity.org/2021/formulas/physics/college/nct0ulpu8a9borsau6k5q3ales423wvy08.png)
So
![3.7* 10^3=9* 10^9* (q)/(0.21^2)](https://img.qammunity.org/2021/formulas/physics/college/h0koprl7988sq9gtevmmpsxw1wk9lfk37i.png)
![q=1.81* 10^(-8)C](https://img.qammunity.org/2021/formulas/physics/college/6m8vjpwefn6vbo26cz2pg31ac54qggfyk6.png)
So charge on the sphere will be equal to
![q=1.81* 10^(-8)C](https://img.qammunity.org/2021/formulas/physics/college/6m8vjpwefn6vbo26cz2pg31ac54qggfyk6.png)