Question

Count input length without spaces, periods, or commas Given a line of text as input, output the number of characters excluding spaces, periods, or commas. You may assume that the input string will not exceed 50 characters.

Ex: If the input is:
Listen, Mr. Jones, calm down.
the output is:
21
Note: Account for all characters that aren't spaces, periods, or commas (Ex: "r", "2", "!").
Can I get this in C programming please?

Answer 1

user_text = input()

import re

string = ( "listen, Mr. Jones, calm down.")

print(len(re.sub(r'[,.\s]+', '', string)))

Step-by-step explanation:

Answer 2

This program is implemented in C++ using dev C++. The solution of this answer along with running code is given below in explanation section.

Step-by-step explanation:

#include <iostream>

#include<string>

using namespace std;

int main()

{

string str;

cout<<"Enter String \\";

getline(cin,str);/* getLine() function get the complete lines, however, if you are getting string without this function, you may lose date after space*/

//cin>>str;

int count = 0;// count the number of characeter

for (int i = 1; i <= str.size(); i++)//go through one by one character

{

if ((str[i]!=32)&&(str[i]!=44)&&(str[i]!=46))//do not count period, comma or space

{

++ count;//count the number of character

}

}

cout << "Number of characters are = "; //display

cout << count;// total number of character in string.

return 0;

}

}