Question

An incandescent light bulb can be regarded as a resistor. If its power output is 100W, calculate the resistance of the light bulb and the current drawn by the light bulb, assuming the voltage of the power source is 110V.

Answer 1

Answer:
`121\ \Omega`

`0.909\ A`

Step-by-step explanation:

Given

Power
`P=100\ W`

Voltage applied
`V=110\ V`

Resistance of the bulb is given by

`P=(V^2)/(R)`

`100=(110^2)/(R)`

`R=(12100)/(100)`

`R=121\ \Omega`

Current drawn by the Power source is given by

`P=V\cdot I`

`I=(P)/(V)`

`I=(100)/(110)`

`I=0.909\ A`