Answer:
(A) Yes, it is true that more that 50% of the sampled angles are smaller than 15 degrees, as asserted in the paper.
(B) The proportion of the sampled angles are at least 30 degrees is 15.2%.
(C) The probability of angles between 10° and 25° is less than 50%.
(D) The data is right skewed.
Explanation:
Consider the frequency distribution table below.
(A)
Compute the probability of angles less than 15° as follows:
P (X < 15°) = P (0° ≤ X ≤ 5°) + P (5° ≤ X ≤ 10°) + P (10° ≤ X ≤ 15°)
= 0.177 + 0.166 + 0.175
= 0.518
≈ 51.8%
Yes, it is true that more that 50% of the sampled angles are smaller than 15 degrees, as asserted in the paper.
(B)
Compute the probability of angles at least 30° as follows:
P (X ≥ 30°) = P (30° ≤ X ≤ 40°) + P (40° ≤ X ≤ 60°) + P (60° ≤ X ≤ 90°)
= 0.078 + 0.044 + 0.030
= 0.152
≈ 15.2%
Thus, the proportion of the sampled angles are at least 30 degrees is 15.2%.
(C)
Compute the probability of angles between 10° and 20° as follows:
P (10° ≤ X ≤ 20°) = P (10° ≤ X ≤ 15°) + P (15° ≤ X ≤ 20°)
= 0.175 + 0.136
= 0.311
Compute the probability of angles between 10° and 30° as follows:
P (10° ≤ X ≤ 300°) = P (10° ≤ X ≤ 15°) + P (15° ≤ X ≤ 20°) + P (20° ≤ X ≤ 30°)
= 0.175 + 0.136 + 0.194
= 0.505
Then the probability of angles between 10° and 25° is less than 50%.
(D)
The histogram is shown below.
From the histogram it can be seen that the graph has a long tail towards the right or most of the observations are accumulated towards the left of the graph.
This implies that the data is positively skewed.
For a positively skewed data the Mean > Median > Mode.