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A very long insulating cylindrical shell of radius 6.00 cm carries a charge of 8.50 μC/m (linear charge density) spreading uniformly over its outer surface. What would a voltmeter read if it is connected between (a) the surface of the cylinder and 4.00 cm away (outward) from the surface, and (b) the surface and a point 1.00 cm from the central axis of the cylinder?

1 Answer

4 votes

Answer:

(a). The potential is 78.0 kV.

(b). The potential is zero.

Step-by-step explanation:

Given that,

Radius = 6.00

Charge density = 8.50 μC/m

(a). The surface of the cylinder and 4.00 cm away from the surface,

We need to calculate the voltage

Using formula of potential


V=(\lambda)/(2\pi\epsilon_(0))ln((r)/(R))

Put the value into the formula


V=(8.5*10^(-6))/(2\pi*8.85*10^(-12))ln((6+4)/(6))


V=78.0\ kV

(b). The surface and a point 1.00 cm from the central axis of the cylinder

Here, r = R

We need to calculate the voltage

Using formula of potential


V=(\lambda)/(2\pi\epsilon_(0))ln((r)/(R))

Put the value into the formula


V=(8.5*10^(-6))/(2\pi*8.85*10^(-12))ln(1)


V=0\ kV

Hence, (a). The potential is 78.0 kV.

(b). The potential is zero.

User Eugene Podskal
by
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