Answer:
P(X ≤ 45)=0.2643
Explanation:
We were given that the random variable X is normally distributed, with mean
μ=50 and standard deviation σ=8.
We want to compute the probability, P(X ≤ 45).
First, we need to calculate the z-score of X=45 using
![Z=(X-\mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xjryp8ydeqt32yspvlaxie9csx43qbw8sp.png)
We substitute these values to get:
![Z=(45-50)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tiddovhgflop0rvhl8pixh3d26mqiyz5xk.png)
![Z=(-5)/(8) =-0.63](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tm1kqvsq75hd0djqktcybwc7xa7itqz79a.png)
We now read area that corresponds to -0.63 in the standard normal distribution table.
This gives us P(X ≤ 45)=0.2643