Answer:
16.79 M
Step-by-step explanation:
Given data
- Mass of KI (solute): 390.1 g
- Volume of solution: 140.0 mL = 0.1400 L
First, we will calculate the moles of KI, considering its molar mass is 166.00 g/mol.
390.1 g × (1 mol/166.00 g) = 2.350 mol
The molarity of KI is:
M = moles of solute / liters of solution
M = 2.350 mol / 0.1400 L
M = 16.79 M