Answer:
Explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
The line passes through (2,-1) and (4,5),
y2 = 11
y1 = 5
x2 = 10
x1 = 4
Slope,m = (11 - 5)/(10 - 4) = 6/6 = 1
To determine the intercept, we would substitute x = 4, y = 5 and
m = 1 into
y = mx + c. It becomes
5 = 1 × 4 + c = c + 4
c = 5 - 4 = 1
The equation becomes
y = x + 1
The standard form is represented as
Ax + By + C = 0
y - x - 1 = 0
Multiplying through by - 1, it becomes
x - y + 1 = 0