Answer:
Explanation:
Since the weight of the products are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weight of the product.
µ = mean weight
σ = standard deviation
From the information given,
µ = 4 ounces
Variance = 0.25²
σ = √variance = √0.25² = 0.25
We want to find the probability that a randomly selected unit from a recently manufactured batch weighs no more than 3.5 ounces. It is expressed as
P(x ≤ 3.5)
For x = 3.5,
z = (3.5 - 4)/0.25 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.0228