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How many atoms are in 437g of silver
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How many atoms are in 437g of silver

User Envin
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2 Answers

3 votes

Answer:

The answer to the question is 6.023

User Hyunyoung
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5.3k points
2 votes

Answer: 2.44 x10²⁴ atoms Ag

Explanation: solution:

Convert mass of Ag to moles then convert moles to atoms of Ag using Avogadro's number.

437 g Ag x 1 mole Ag / 108 g Ag x 6.022x10²³ atoms Ag / 1 mole Ag

= 2.44x10²⁴ atoms Ag

User Vignesh Jayavel
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