Question

A website says that you'll need 48 fifty-pound bags of sand to fill a sandbox that measures 8 ft by 8 ft by 1 ft. How many bags would you need for sandbox 6 ft by 4 ft by 1 ft?

Answer 1

The sandbox 6 ft by 4 ft by 1 ft require 18 bags of fifty-pound bags of sand to fill the sandbox.

Explanation:

The dimensions of the sandbox 1 is: 8 ft by 8 ft by 1 ft.

The volume of the sandbox 1 is:

`Volume_(1)=8* 8* 1= 64\ ft^(3)`

The The dimensions of the sandbox 2 is: 6 ft by 4 ft by 1 ft.

The volume of the sandbox 2 is:

`Volume_(2)=6* 4* 1= 24\ ft^(3)`

Use unitary method to determine the number of bags of sand required to fill the sand box of dimensions 6 ft by 4 ft by 1 ft.

Sandbox with volume 64 ft³ requires 48 bags.

Then a sandbox with volume 1 ft³ will require:
`(48)/(64)` bags.

Then a sandbox with volume 24 ft³ will require:
`(48)/(64)*24=18` bags.

Thus, the sandbox 2 require 18 bags of fifty-pound bags of sand to fill the sandbox.

Answer 2

Explanation:

The website says that you'll need 48 fifty-pound bags of sand to fill a sandbox that measures 8 ft by 8 ft by 1 ft.

The formula for determining the volume of the box is expressed as

Volume = L × W × H

Volume of the sandbox = 8 × 8 × 1 = 64 feet²

The volume of the sandbox to be filled is

Volume = 6 × 4 × 1 = 24 feet²

Therefore, the number of bags needed to fill this sandbox is

(48 × 24)/64 = 1152/64 = 18 fifty-pound bags