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How many atoms are in 313.5 L of Bromine (Br) gas

2 Answers

4 votes

Answer:

The answer to the question is 79.91

User Jpenzer
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6 votes

Answer:

313.5 L of Br2 contains 8.428x10^24 atoms

Step-by-step explanation:

Imol of Br2 occupies 22.4L

Therefore Xmol of Br2 will occupy 313.5L i.e

Xmol of Br2 = 313.5/22.4 = 14moles

1mole of Br2 contains 6.02x10^23 atoms.

Therefore 14moles of Br2 will contain = 14x6.02x10^23 = 8.428x10^24 atoms

Therefore 313.5 L of Br2 contains 8.428x10^24 atoms

User Mark Tomlin
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3.5k points