Question

This is a special right triangle (30-60-90) and I can do most of them but this one confuses me how do you set up the problem?

Answer 1

`x =(40)/(3)√(3) ; y =(20)/(3)√(3)`

Explanation:

standart special right triangle with some square root operations

let the triangle has side a, 2a, and a√3.

since a√3 = 20, then
`a=(20)/(√(3)) * (√(3))/(√(3))=(20)/(3)√(3)`

Answer 2

Explanation:

With 60 degrees as the reference angle,

x represents the hypotenuse of the right angle triangle.

y represents the adjacent side of the right angle triangle

20 represents the opposite side of the right angle triangle.

To determine x, we would apply the

Sine trigonometric ratio. It is expressed as

Sin θ = opposite side/hypotenuse.

Sin 60 = 20/x

x = 20/Sin60 = 20/0.8660

x = 23.1

To determine y, we would apply the

Tangent trigonometric ratio. It is expressed as

Tan θ = opposite side/adjacent side.

Tan 60 = 20/y

y = 20/Tan60 = 20/1.7321

y = 11.5