Question

A plane stops from 250 mph in 25 seconds.
- Calculate the planes acceleration.

Answer 1

The plane requires a negative acceleration or deceleration of 36000 mph² to come to rest from speed of 250 mph.

Step-by-step explanation:

So the initial velocity of plane in this case is 250 mph and time taken by the plane to stop is 25 s. First we have to convert the seconds unit of time to hour unit. So time taken by the plane to come to stop is

`t = (25)/(3600) h`

Since acceleration is the measure of change in velocity with time. Here the initial velocity is 250 mph and final velocity is zero as the plane is said to stop in 25 seconds.

Thus, acceleration =
`(0-250)/((25)/(3600) )=(-250*3600)/(25)`

So acceleration = -36000
`mph^(2)`

Thus, the plane requires a negative acceleration or deceleration of 36000 mph² to come to rest from speed of 250 mph.