97.4k views
1 vote
3 2 ? start fraction, 2, divided by, 3, end fraction of the doughnuts in a box have frosting. \dfrac12 2 1 ? start fraction, 1, divided by, 2, end fraction of the doughnuts with frosting have sprinkles. What fraction of the doughnuts in the box have frosting and sprinkles?

1 Answer

3 votes

Answer:


(1)/(3) of the doughnuts in the box have frosting and sprinkles.

Explanation:

If there are
x doughnuts in the box. Then,
(2)/(3) * x = (2x)/(3) of the doughnuts in the box have frosting. Therefore,
(1)/(2) * (2x)/(3) = (1)/(3)x of the doughnuts with frosting have sprinkles. This implies that
(1)/(3) of the doughnuts in the box have frosting and sprinkles.

User Eden
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.