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3 2 ? start fraction, 2, divided by, 3, end fraction of the doughnuts in a box have frosting. \dfrac12 2 1 ? start fraction, 1, divided by, 2, end fraction of the doughnuts with frosting have sprinkles. What fraction of the doughnuts in the box have frosting and sprinkles?

1 Answer

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Answer:


(1)/(3) of the doughnuts in the box have frosting and sprinkles.

Explanation:

If there are
x doughnuts in the box. Then,
(2)/(3) * x = (2x)/(3) of the doughnuts in the box have frosting. Therefore,
(1)/(2) * (2x)/(3) = (1)/(3)x of the doughnuts with frosting have sprinkles. This implies that
(1)/(3) of the doughnuts in the box have frosting and sprinkles.

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