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A female that is homozygous for an X-linked dominant trait is expected to pass on the trait to what proportion of her children?

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Answer:

She has a 50% chance of passing the gene to her likeable sons and daughters in equal proportions of 50-50% assuming the inheritance is based on Mendel's Mono hybrid cross with each of the sex-linked gene moving into each of the offspring boys and girls.

Assuming the husband is normal . the man will give normal Y-chromosomes and the mother will give either of defective allele(XX), so the boys, will all be sex-linked for the traits. Since boys sex genotypes are XY, XY However.the girls will be carrier.

if the man also has the trait (defective X , but free Y, then) , all the girls will have the sex linked -traits, and be dominant for sex-linked allele like the mother. since two defective sex-linked traits of XX( one from the father, and one from the mother will be inherited will be inherited.

Step-by-step explanation:

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