Question

What is the change in the gravitational potential energy of the system of blocks and Earth when the 3.7-kg block has dropped 0.48 m ?

Answer 1

The PE of system changed from 17.40 joules to 0 joules

Step-by-step explanation:

Here m= mass of block = 3.7 kg

g= gravitational acceleration = 9.8 m/sec2

h= Height = 0.48 m

Potential energy at point A

PE= mgh = 3.7 × 9.8 × 0.48= 17.40 j

At point B 0.48 m below on ground

PE = mgh =3.7 × 9.8 × 0 = 0