Question

Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.

Answer 1

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

`Molarity=(n)/(W_s)`

where,

n = moles of solute

`W_s` = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )=
`moles* {\text {Molar Mass}}=0.759* 18=13.7g=0.0137kg`

Now put all the given values in the formula of molality, we get

`Molality=(0.241)/(0.0137kg)=17.6mole/kg`

Therefore, the molality of solution is 17.6 mole/kg