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Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.

m∠DEF = 60°.

Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F-example-1

1 Answer

3 votes

Answer:

The area of the triangle is
√(3)

Explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is =
(1)/(2)(base * height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE =
√((0-1)^2 + (0-1)^2)

DE =
\sqrt{(-1) ^2 + (-1)^2

DE =
√(1+1)

DE =
√(2)

Base =
√(2)

Height is DF

DF =
tan(60^(\circ)) * DE

DF =
√(3) * DE

DF =
√(3) *√(2)

Now, the area of the triangle is

=
(1)/(2)({√(2))(√(3) * √(2))

=
(1)/(2)({√(2))(√(3) √(2))

=
(1)/(2)(2√(3) )

=
√(3)

Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F-example-1
User Rdowell
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