Question

A boy is 6 ft. tall. The distance from the boy to a mirror is 8 ft. From the mirror to the house is 16 ft. How high is the top of the house?

Answer 1

12 ft.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given

Height of boy
`h(EF)=6\ ft`

Distance of boy from mirror
`FC=8\ ft`

Distance of house is
`BC=16\ ft`

We know angle of incident and angle of reflection is same therefore

`\angle FEC=\angle CAB`

thus
`\tan \theta =(FC)/(EF)---1`

Also
`\tan \theta =(BC)/(AB)----2`

From 1 and 2 we got

`(FC)/(EF)=(BC)/(AB)`

`AB=(16* 6)/(8)`

`AB=12\ m`