Question

Solve the following system of equations
{y=1/6x+8
{y=3/4x+1 NEED HELP ASAP

Answer 1

x = 12 and y = 10

Solution:

Given system of equations are

`y=(1)/(6) x+8` – – – – (1)

`y=(3)/(4) x+1` – – – – (2)

Both are equations of y.

So, we can equate both the equations.

`$(1)/(6) x+8=(3)/(4) x+1`

Arrange like terms one sides.

`$(1)/(6) x-(3)/(4) x=1-8`

`$(1)/(6) x-(3)/(4) x=-7`

Take LCM of the denominators.

LCM of 6 and 4 = 12

Make the denominators same.

`$(1* 2)/(6* 2) x-(3* 3)/(4* 3) x=-7`

`$(2)/(12) x-(9)/(12) x=-7`

`2x-9x=-7*12`

`-7x=-84`

Divide both side of the equation by –7, we get

x = 12

Substitute x = 12 in equation (1).

`$y=(1)/(6) * 12+8`

`$y=2+8`

y = 10

Hence x = 12 and y = 10.