1 Answer

Lyron · Answer 1 · 2021-12-25T18:33:37+0000

Answer:

Step-by-step explanation:

Given

Rock is dropped from a height of
$h=164\ m$

Rock is drooped so initial velocity is zero i.e.
u=0

Time taken to fall
$82\ m$ is given by

y=ut+(1)/(2)at^2

where

y=displacement

u=initial velocity

a=acceleration

t=time

164=0+(1)/(2)gt^2

$t=\sqrt{(2* 82)/(9.8)}$

$t=4.09\ s$

Now time taken to fall another 82 m

We can calculate this time by first calculating time taken to cover 82+82 m and then subtracting the time taken to cover 82 m

$t_2=\sqrt{(2* 164)/(9.8)}$

$t_2=5.78\ s$

time taken
$=t_2-t=5.78-4.09=1.69\ s$

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